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If the circle x^(2) +y^(2) + 2gx + 2fy ...

If the circle ` x^(2) +y^(2) + 2gx + 2fy + c = 0 ` bisects the circumference of the circle
` x^(2) +y^(2) + 2g'x + 2f'y + c' = 0 ` , them the length of the common chord of these two circles is

A

`2sqrt(g^2+f^2-c)`

B

`2sqrt(g^('2)+f^('2)-c^('))`

C

`2sqrt(g^2+f^2+c)`

D

`2sqrt(g^(|2)+f^(|2)+c^(|))`

Text Solution

Verified by Experts

The correct Answer is:
B
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