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The circles having radii 1, 2, 3 touch c...

The circles having radii 1, 2, 3 touch cach other externally then the radius of the circle which cuts three circles orthogonally is

A

1

B

4

C

6

D

2

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem of finding the radius of a circle that cuts three circles with radii 1, 2, and 3 orthogonally, we can follow these steps: ### Step 1: Identify the given circles and their radii We have three circles with the following radii: - Circle A: \( r_1 = 1 \) - Circle B: \( r_2 = 2 \) - Circle C: \( r_3 = 3 \) ### Step 2: Calculate the distances between the centers of the circles Since the circles touch each other externally, the distances between their centers can be calculated as follows: - Distance \( AB = r_1 + r_2 = 1 + 2 = 3 \) - Distance \( AC = r_1 + r_3 = 1 + 3 = 4 \) - Distance \( BC = r_2 + r_3 = 2 + 3 = 5 \) ### Step 3: Calculate the semi-perimeter \( S \) The semi-perimeter \( S \) of the triangle formed by the centers of the circles can be calculated using the formula: \[ S = \frac{AB + AC + BC}{2} = \frac{3 + 4 + 5}{2} = \frac{12}{2} = 6 \] ### Step 4: Calculate the area \( \Delta \) of the triangle Using Heron's formula, the area \( \Delta \) can be calculated as: \[ \Delta = \sqrt{S(S - AB)(S - AC)(S - BC)} \] Substituting the values: \[ \Delta = \sqrt{6(6 - 3)(6 - 4)(6 - 5)} = \sqrt{6 \times 3 \times 2 \times 1} = \sqrt{36} = 6 \] ### Step 5: Use the formula to find the radius \( R \) of the orthogonal circle The radius \( R \) of the circle that cuts the three circles orthogonally is given by the formula: \[ R = \frac{\Delta}{S} \] Substituting the values we found: \[ R = \frac{6}{6} = 1 \] ### Conclusion The radius of the circle that cuts the three circles orthogonally is \( R = 1 \). ### Final Answer The radius of the circle which cuts the three circles orthogonally is **1**.
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