`Cl_2` reacts with water and forms 

Options

A. `HCl + HOCl`
B. `HCl + O_2 + O_3`
C. `HCl + HOCl + O_3`
D. `HOCl + O_2`

Answer

To determine the products formed when chlorine gas (Cl₂) reacts with water (H₂O), we can follow these steps:

### Step 1: Understand the Reaction
Chlorine gas reacts with water, and this reaction is known as a disproportionation reaction. In this type of reaction, one species is simultaneously oxidized and reduced.

### Step 2: Write the Reaction Equation
The reaction can be represented as:
\[ \text{Cl}_2 + \text{H}_2\text{O} \rightarrow \text{HCl} + \text{HOCl} \]
Here, HCl is hydrochloric acid, and HOCl is hypochlorous acid.

### Step 3: Identify the Products
From the reaction equation, we can see that the products formed are:
1. Hydrochloric acid (HCl)
2. Hypochlorous acid (HOCl)

### Step 4: Consider Further Reactions
Since hydrochloric acid (HCl) is acidic, it can further react with water. The reaction can be represented as:
\[ \text{HCl} + \text{H}_2\text{O} \rightarrow \text{H}_3\text{O}^+ + \text{Cl}^- \]
This indicates that HCl dissociates in water to form hydronium ions (H₃O⁺) and chloride ions (Cl⁻).

### Step 5: Conclusion
The overall reaction of chlorine with water leads to the formation of hydrochloric acid and hypochlorous acid, and the solution becomes slightly acidic due to the presence of HCl.

### Final Answer
The products formed when Cl₂ reacts with water are hydrochloric acid (HCl) and hypochlorous acid (HOCl).

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