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Cl2 (or) Br2 (or) I2 reacts with cold an...

`Cl_2` (or) `Br_2 `(or)` I_2` reacts with cold and dilute alkali solution to form 

A

Halide + Hypohalite

B

Halide + Hypohalite + `H_2O`

C

Halide + halite

D

Halide + Halate + `H_2O`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the question regarding the reaction of `Cl_2`, `Br_2`, or `I_2` with cold and dilute alkali solutions, we can follow these steps: ### Step-by-Step Solution 1. **Identify the Reactants**: The reactants in this case are chlorine (`Cl_2`), bromine (`Br_2`), or iodine (`I_2`), and they are reacting with a cold and dilute alkali solution, which is typically sodium hydroxide (`NaOH`). 2. **Understand the Reaction Conditions**: The reaction occurs under cold and dilute conditions, which influences the products formed. 3. **Write the General Reaction for Chlorine**: - When chlorine reacts with cold and dilute sodium hydroxide, the products formed are sodium chloride (`NaCl`), sodium hypochlorite (`NaOCl`), and water (`H_2O`). - The balanced equation can be written as: \[ Cl_2 + 2NaOH \rightarrow NaCl + NaOCl + H_2O \] 4. **Write the General Reaction for Bromine**: - Similarly, when bromine reacts with cold and dilute sodium hydroxide, the products formed are sodium bromide (`NaBr`), sodium hypobromite (`NaBrO`), and water. - The balanced equation can be written as: \[ Br_2 + 2NaOH \rightarrow NaBr + NaBrO + H_2O \] 5. **Write the General Reaction for Iodine**: - For iodine, the reaction with cold and dilute sodium hydroxide produces sodium iodide (`NaI`), sodium hypoiodite (`NaIO`), and water. - The balanced equation can be written as: \[ I_2 + 2NaOH \rightarrow NaI + NaIO + H_2O \] 6. **Summarize the Products**: From the reactions, we can summarize that: - Chlorine produces: Sodium chloride (`NaCl`), Sodium hypochlorite (`NaOCl`), and water (`H_2O`). - Bromine produces: Sodium bromide (`NaBr`), Sodium hypobromite (`NaBrO`), and water (`H_2O`). - Iodine produces: Sodium iodide (`NaI`), Sodium hypoiodite (`NaIO`), and water (`H_2O`). 7. **Conclusion**: Therefore, the general products formed when `Cl_2`, `Br_2`, or `I_2` react with cold and dilute alkali solution are halides, hypohalides, and water. ### Final Answer The reaction of `Cl_2`, `Br_2`, or `I_2` with cold and dilute alkali solution forms halides, hypohalides, and water. ---
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