The products formed when `Cl_2` reacts with excess of `NH_3` are

Options

A. `NCl_3 + HCl`
B. `N_2 + HCl`
C. `NCl_3 + N_2`
D. `N_2 + NH_4 Cl`

Answer

To determine the products formed when chlorine (Cl₂) reacts with an excess of ammonia (NH₃), we can follow these steps:

### Step 1: Write the Reaction Equation
When chlorine gas reacts with ammonia, the initial reaction can be represented as:
\[ \text{Cl}_2 + \text{NH}_3 \rightarrow \text{Products} \]

### Step 2: Identify the Products
The reaction between chlorine and ammonia typically produces nitrogen trichloride (NCl₃) and hydrochloric acid (HCl). The balanced equation for this reaction can be written as:
\[ \text{Cl}_2 + 2 \text{NH}_3 \rightarrow NCl_3 + 3 \text{HCl} \]

### Step 3: Balance the Equation
To balance the equation, we ensure that the number of atoms of each element is the same on both sides. The balanced equation is:
\[ \text{Cl}_2 + 2 \text{NH}_3 \rightarrow NCl_3 + 3 \text{HCl} \]

### Step 4: Conclusion
The products formed when chlorine reacts with excess ammonia are nitrogen trichloride (NCl₃) and hydrochloric acid (HCl).

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