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{:("List I", "List II"),("Property", "Or...

`{:("List I", "List II"),("Property", "Order"),("(A) M.Pts", (1) I_2 > Br_(2) > Cl_2>F_2),("(B) B.Pts", (2) Cl > F > Br > I),("(C) Electron affinity", (3) Cl_2 > Br_2 > F_2 > I_2),("(D) Bond dissociation energy" , (4) F_2 > Cl_2 > I_2 > Br_2):}`
The correct match is

A

`{:(A,B,C,D),(1,1,2,3):}`

B

`{:(A,B,C,D),(2,1,3,4):}`

C

`{:(A,B,C,D),(1,2,3,4):}`

D

`{:(A,B,C,D),(1,4,3,2):}`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem of matching the properties of halogens with their respective orders, we will analyze each property one by one and determine the correct matches. ### Step 1: Analyze Melting Points (M.Pts) - **Observation**: As we move down the group of halogens (F, Cl, Br, I), the state of matter changes from gas (F and Cl) to liquid (Br) to solid (I). - **Conclusion**: The melting point increases down the group. Thus, the order is: - I₂ > Br₂ > Cl₂ > F₂ - **Match**: (A) M.Pts corresponds to (1) I₂ > Br₂ > Cl₂ > F₂. ### Step 2: Analyze Boiling Points (B.Pts) - **Observation**: Similar to melting points, the boiling points also increase down the group due to stronger intermolecular forces in larger atoms. - **Conclusion**: The order is: - I₂ > Br₂ > Cl₂ > F₂ - **Match**: (B) B.Pts corresponds to (2) I₂ > Br₂ > Cl₂ > F₂. ### Step 3: Analyze Electron Affinity - **Observation**: Electron affinity generally increases with decreasing atomic size. However, fluorine, being the smallest, has a high electron-electron repulsion which lowers its electron affinity compared to chlorine. - **Conclusion**: The order is: - Cl > F > Br > I - **Match**: (C) Electron affinity corresponds to (2) Cl > F > Br > I. ### Step 4: Analyze Bond Dissociation Energy - **Observation**: Bond dissociation energy is influenced by bond length. Larger atoms have longer bonds and thus lower bond dissociation energy. Fluorine has high electron-electron repulsion due to its small size. - **Conclusion**: The order is: - F₂ > Cl₂ > Br₂ > I₂ - **Match**: (D) Bond dissociation energy corresponds to (3) F₂ > Cl₂ > Br₂ > I₂. ### Final Matches - (A) M.Pts corresponds to (1) I₂ > Br₂ > Cl₂ > F₂ - (B) B.Pts corresponds to (2) I₂ > Br₂ > Cl₂ > F₂ - (C) Electron affinity corresponds to (2) Cl > F > Br > I - (D) Bond dissociation energy corresponds to (3) F₂ > Cl₂ > Br₂ > I₂ ### Correct Match Summary - A → 1 - B → 2 - C → 2 - D → 3
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