Home
Class 12
CHEMISTRY
Bond dissociation energies of HF, HCl, H...

Bond dissociation energies of HF, HCl, HBr follow the order

A

`HCI gt HBr gt HF`

B

`HF gt HBr gt HCI`

C

`HF gt HCIgt HBr`

D

`HBr gt HCI gt HF`

Text Solution

AI Generated Solution

The correct Answer is:
To determine the order of bond dissociation energies of HF, HCl, and HBr, we will analyze the factors affecting bond strength and dissociation energy. ### Step-by-Step Solution: 1. **Understanding Bond Dissociation Energy**: Bond dissociation energy is the energy required to break a bond between two atoms in a molecule. Higher bond dissociation energy indicates a stronger bond. 2. **Identify the Halogen Group**: HF (hydrogen fluoride), HCl (hydrogen chloride), and HBr (hydrogen bromide) are all compounds formed between hydrogen and halogens (Group VIIA elements). The halogens in order of increasing atomic size are: Fluorine (F), Chlorine (Cl), and Bromine (Br). 3. **Consider Atomic Size**: As we move down the group from fluorine to bromine, the atomic size increases. Larger atomic size generally leads to longer bond lengths, which typically results in weaker bonds. Therefore, we can expect the bond strengths to decrease from HF to HCl to HBr. 4. **Analyze Electronegativity**: Electronegativity is the ability of an atom to attract electrons. Fluorine is the most electronegative element, followed by chlorine and then bromine. Higher electronegativity in HF leads to a stronger bond due to the greater attraction between the hydrogen and fluorine atoms. 5. **Evaluate Hydrogen Bonding in HF**: HF exhibits strong hydrogen bonding due to the high electronegativity of fluorine. This additional interaction contributes to a higher bond dissociation energy compared to HCl and HBr, which do not exhibit hydrogen bonding to the same extent. 6. **Conclusion**: Based on the above factors, we can conclude that the bond dissociation energies follow this order: \[ \text{Bond Dissociation Energy Order: } HF > HCl > HBr \] Therefore, the correct answer is that HF has the highest bond dissociation energy, followed by HCl, and then HBr. ### Final Answer: The order of bond dissociation energies is: \[ \text{HF} > \text{HCl} > \text{HBr} \]
Promotional Banner

Similar Questions

Explore conceptually related problems

Define bond dissociation energy.

The bond dissociation energies of X_2, Y_2 and XY are in the ratio of 1 : 0.5 : 1. DeltaH for the formation of XY is -200 kJ mol^(-1) . The bond dissociation energy of X_2 will be

Which of the following represents the true order of bond dissociation energy of the idicated C-H bond of the following molecules?

The correct order of bond dissociation energies of various C-H bonds present in the compound is

If the bond dissociation energies of XY , X_(2) and Y_(2) are in the ratio of 1:1:0.5 and DeltaH_(f) for the formation of Xy is -200 KJ//mol . The bond dissociation energy of X_(2) will be :-

The bond dissociation energies of gaseous H_(2),Cl_(2) , and HCl are 100, 50 , and 100 kcal mol^(-1) , respectively. Calculate the enthalpy of formation of HCl(g) .

Bond dissociation energy of F_(2) is less that of Cl_(2) give reason.

State how the dissociation energy changes with the bond order?