`NH_3 + 3F_2 to A+ 3HF`
The correct statement regarding A is 

Options

A. `sp^3`, Tetrahedral, no lone pair
B. `sp^(3)`, Pyramidal, one lone pair
C. `sp`, linear, no lone pair
D. `sp^(3)`, angular, two lone pairs

Answer

To solve the question regarding the reaction \( NH_3 + 3F_2 \to A + 3HF \) and to determine the correct statement regarding \( A \), we can follow these steps:

### Step-by-Step Solution:

1. **Identify the Reactants and Products**:
- The reactants are ammonia (\( NH_3 \)) and fluorine gas (\( F_2 \)).
- The products include \( A \) and hydrogen fluoride (\( HF \)).

2. **Balance the Reaction**:
- The reaction shows that 3 molecules of \( F_2 \) react with 1 molecule of \( NH_3 \) to produce 3 molecules of \( HF \).
- The remaining product \( A \) must be determined.

3. **Determine the Composition of Product \( A \)**:
- In the reaction, nitrogen from \( NH_3 \) is likely to form a compound with fluorine.
- Since 3 molecules of \( F_2 \) are used, and each \( F_2 \) provides 2 fluorine atoms, a total of 6 fluorine atoms are available.
- The nitrogen atom from \( NH_3 \) can bond with 3 of these fluorine atoms to form \( NF_3 \).

4. **Write the Product**:
- Therefore, the product \( A \) is \( NF_3 \).

5. **Analyze the Structure of \( NF_3 \)**:
- \( NF_3 \) has nitrogen bonded to three fluorine atoms.
- The nitrogen atom has one lone pair of electrons.

6. **Determine the Hybridization and Shape**:
- The hybridization of \( NF_3 \) can be determined by counting the number of bonds and lone pairs:
- 3 bonded pairs (N-F bonds) and 1 lone pair on nitrogen.
- This gives a total of 4 regions of electron density, which corresponds to \( sp^3 \) hybridization.
- The shape of \( NF_3 \) is trigonal pyramidal due to the presence of the lone pair.

7. **Conclusion**:
- The correct statement regarding \( A \) (which is \( NF_3 \)) is that it has a trigonal pyramidal shape and \( sp^3 \) hybridization.

### Final Answer:
The correct statement regarding \( A \) is that it has a trigonal pyramidal shape and \( sp^3 \) hybridization.