Hybridisation of the central atom in `Cl_2O` molecule is 

Options

A. `sp^2`
B. `sp^3`
C. `sp^3d`
D. `sp^3 d^2`

Answer

To determine the hybridization of the central atom in the Cl₂O molecule, we can follow these steps:

### Step-by-Step Solution:

1. **Identify the Central Atom**:
In the Cl₂O molecule, the central atom is oxygen (O). Chlorine (Cl) atoms are terminal atoms.

2. **Determine the Valence Electrons**:
Oxygen has 6 valence electrons (as it is in group 16 of the periodic table).

3. **Count the Monovalent Atoms**:
Chlorine is a monovalent atom, meaning it can form one bond. Since there are two chlorine atoms in Cl₂O, we have 2 monovalent atoms.

4. **Calculate the Hybridization Number (H)**:
The hybridization number can be calculated using the formula:
\[ H = \frac{(S + M)}{2} \]
where:
- \(S\) = number of valence electrons of the central atom (O) = 6
- \(M\) = number of monovalent atoms (Cl) = 2

Plugging in the values:
\[ H = \frac{(6 + 2)}{2} = \frac{8}{2} = 4 \]

5. **Determine the Hybridization Type**:
A hybridization number of 4 corresponds to \(sp^3\) hybridization. This indicates that the central atom (oxygen) forms four hybrid orbitals.

6. **Conclusion**:
Therefore, the hybridization of the central atom in the Cl₂O molecule is \(sp^3\).

### Final Answer:
The hybridization of the central atom in Cl₂O is \(sp^3\).

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