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Most powerful oxidant among halogens and...

Most powerful oxidant among halogens and most powerful reductant among halide ions are 

A

`F_2, F^(-)`

B

`F_(2), I^(-)`

C

`I_(2),I^(-)`

D

`I_(2), F^(-)`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the question regarding the most powerful oxidant among halogens and the most powerful reductant among halide ions, we can follow these steps: ### Step 1: Identify the Halogens The halogens are elements in Group 17 of the periodic table. They include: - Fluorine (F) - Chlorine (Cl) - Bromine (Br) - Iodine (I) ### Step 2: Determine the Most Powerful Oxidant An oxidant is a substance that gains electrons and is reduced in a chemical reaction. Among the halogens, we need to determine which one is the strongest oxidizing agent. - **Fluorine (F2)** is known to be the strongest oxidizing agent among the halogens. This is because: - It has a high standard reduction potential. - It has a small atomic size, which allows it to accept electrons readily. - It has high electronegativity and low dissociation energy. The standard electrode potential for the reduction of fluorine is: \[ \text{F}_2 + 2e^- \rightarrow 2\text{F}^- \] with a standard reduction potential of +2.87 volts. ### Step 3: Identify the Halide Ions The halide ions are the anions formed from halogens: - Fluoride (F^-) - Chloride (Cl^-) - Bromide (Br^-) - Iodide (I^-) ### Step 4: Determine the Most Powerful Reductant A reductant is a substance that loses electrons and is oxidized in a chemical reaction. Among the halide ions, we need to determine which one is the strongest reducing agent. - **Iodide (I^-)** is the strongest reductant among the halide ions. This is because: - It is the largest ion among the halides, which makes it less electronegative. - It has a greater tendency to lose electrons compared to the other halide ions. ### Conclusion - The most powerful oxidant among halogens is **Fluorine (F2)**. - The most powerful reductant among halide ions is **Iodide (I^-)**. ### Final Answer The correct answer is: - **Fluorine (F2)** as the most powerful oxidant among halogens. - **Iodide (I^-)** as the most powerful reductant among halide ions. ---
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