The oxidation state of Xe in XeO3, and bond angle in it are 

Options

A. a. `+6, 109^@`
B. b. `+8, 103^@`
C. c. `+6, 103^@`
D. d. `+8, 120^@`

Answer

To determine the oxidation state of xenon (Xe) in xenon trioxide (XeO3) and the bond angle in the molecule, we can follow these steps:

### Step 1: Determine the oxidation state of Xe in XeO3
1. **Assign oxidation states**: Let the oxidation state of xenon (Xe) be represented as \( X \). The oxidation state of oxygen (O) is typically \(-2\).
2. **Set up the equation**: Since there are three oxygen atoms in XeO3, we can express the total oxidation states as:
\[ X + 3(-2) = 0 \]
This simplifies to:
\[ X - 6 = 0 \]
3. **Solve for X**: Rearranging the equation gives:
\[ X = +6 \]
Therefore, the oxidation state of xenon in XeO3 is \( +6 \).

### Step 2: Determine the bond angle in XeO3
1. **Analyze the molecular geometry**: In XeO3, xenon is bonded to three oxygen atoms and has one lone pair of electrons. This results in a total of four regions of electron density around the xenon atom.
2. **Determine hybridization**: With four regions of electron density, the hybridization of the xenon atom can be determined to be \( sp^3 \).
3. **Identify the molecular shape**: The presence of one lone pair and three bond pairs indicates that the shape of the molecule is trigonal pyramidal.
4. **Estimate the bond angle**: The ideal bond angle for a tetrahedral arrangement (which is the basic geometry for \( sp^3 \) hybridization) is \( 109.5^\circ \). However, due to the presence of the lone pair, the bond angle will be slightly less than this. The bond angle in XeO3 is approximately \( 103^\circ \).

### Final Answer
- The oxidation state of Xe in XeO3 is \( +6 \).
- The bond angle in XeO3 is approximately \( 103^\circ \).

---