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A point moves in the plane xy according ...

A point moves in the plane `xy` according to the law `x=a sin omegat`, `y=a(1-cos omega t)`, where a and `omega` are positive constants. Find:
(a) the distance s traversed by the point during the time `tau`,

Text Solution

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x=K sin wt,`v_(x)=(dx)/(dt)=Komega cos omegat`
y=K(1-cos omegat)
`v_(y)=(dy)/(dt)=Komega` ,`v=sqrt(V_(x)^(2)+V_(y)^(2))=komega`
`"Distance"="speedxx"time" =(Komega)t.`
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