A stone is dropped from a height 300 m and at the same time another stone is projected vertically upwards with a velocity of `100m//sec`. Find when and where the two stones meet.

Explanation

To solve the problem of when and where the two stones meet, we can break it down into several steps:

### Step 1: Understand the Motion of Both Stones
- **Stone 1** (dropped from a height of 300 m):
- Initial velocity (u1) = 0 m/s (since it is dropped)
- Height from which it is dropped = 300 m
- Acceleration due to gravity (g) = 9.8 m/s² (acting downwards)

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