A stone is thrown vertically upward with a speed of 10.0 `ms^(-1)` from the edge of a cliff 65 m high.How much later will it reach the bottom of the cliff ? What will be its speed just before hitting the bottom ?

Explanation

To solve the problem step by step, we will break it down into two parts: the upward motion of the stone and the downward motion after it reaches its maximum height.

### Step 1: Calculate the maximum height reached by the stone
1. **Given Data:**
- Initial velocity (u) = 10 m/s (upward)
- Acceleration due to gravity (g) = 10 m/s² (downward)
- Final velocity (v) at maximum height = 0 m/s

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