Velocity and acceleration of a particle at time `t=0`are `u=(2 hati+3 hatj) m//s and a=(4 hati+3 hatj) m//s^2` respectively. Find the velocity and displacement if particle at `t=2s.`

Explanation

Here,acceleration `veca=(4hati+2hatj)m//s^(2)` is constant ,si, we can apply `vecv=vecu+vec(at)` and `vecs=vecut+(1)/(2)vecat^(2)`
Substituting the proper values,we get
`vecv=(2hati+3hatj)+(2)(4hati+2hatj)=(10hati+7hatj)m//s` and
Therefore,velocity and displacement of particle at t=2s are `(10hati+7hatj)` m//s and `(12hati+10hatj)` m respectively.