The acceleration-displacement graph of a particle moving in a straight line is as shown in figure, initial velocity of particle is zero. Find the velocity of the particle when displacement of the particle is `s=12 m`.

Explanation

From the equation `v^(2)-u^(2)`=2as
as=`(v^(2)-u^(2))/(2)`=area under a-s graph
initial velocity u=0,
`therefore as =(v^(2))/(2)`=area under a-s graph
`therefore V=sqrt(2("area under a-s graph"))`
`sqrt([(1)/(2)(2)+6xx2(1)/(2)(2+4)2+(1)/(2)(2)4])2=sqrt(2xx24)=4sqrt(3)ms^(-1)`