An object Is vertically projected with an initial velocity of `20ms^(-1)`.Calculate the distance travelled by the object in 3 seconds.(g=`10ms^(-2)`)

Explanation

To solve the problem of calculating the distance traveled by an object projected vertically with an initial velocity of \(20 \, \text{m/s}\) in \(3\) seconds, we can use the following kinematic equation:

\[ s = ut - \frac{1}{2}gt^2 \]

Where:
- \(s\) = displacement (distance traveled)
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