An object describes 225 m in the first 3s and 400 m in the next 2s.Calculate the velocity after 5s.From the start.

Explanation

To solve the problem, we need to calculate the velocity of the object after 5 seconds, given that it travels 225 m in the first 3 seconds and 400 m in the next 2 seconds. We will use the equations of motion to find the initial velocity and acceleration, and then use that information to find the final velocity.

### Step-by-Step Solution:

1. **Determine the distance traveled in each interval:**
- Distance in the first 3 seconds (t1 = 3s): \( s_1 = 225 \, \text{m} \)
- Distance in the next 2 seconds (t2 = 2s): \( s_2 = 400 \, \text{m} \)

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