For a stone what is the ratio of the distance covered in its 1st, 3rd and 5th seconds of its free fall.

From the top of a tower, a particle is thrown vertically downwards with a velocity of 10 m//s . The ratio of the distances, covered by it in the 3rd and 2nd seconds of the motion is ("Take" g = 10 m//s^2) .

A bus starts from rest and moves whith acceleration a = 2 m/s^2 . The ratio of the distance covered in 6^(th) second to that covered in 6 seconds is

With what speed should a body be thrown upwards so that the distances traversed in 5th second and 6th second are equal?

Time period of a particle executing SHM is 8 sec. At t=0 it is at the mean position. The ratio of the distance covered by the particle in the 1st second to the 2nd second is:

If a ball is thrown vertically upwards with speed u , the distance covered during the last t second of its ascent is

Find the ratio of the distance moved by a free-falling body from rest in fourth and fifth seconds of its journey.

Find the ratio of the distances travelled by a freely falling body in first, second and third second of its fall.

A body starts from rest, what is the ratio of the distance travelled by the body during the 4th and 3rd s?

For the velocity - time graph shown in figure below the distance covered by the body in last two seconds of its motion is what fraction of the total distance covered by it in all the total distance covered by it in all the seven seconds

A body starts from rest and moves with constant acceleration. The ratio of distance covered by the body in nth second to that covered in n second is.