Home
Class 12
PHYSICS
One mole of an ideal gas at standard tem...

One mole of an ideal gas at standard temperature and pressure occupies 22.4 L (molar volume). IF the size of the hydrogent molecule is about 1A. What is the ratio of molar volume to the atomic volume of a mole of hydrogen?

A

`10^4`

B

`10^2`

C

`10^3`

D

`10^(-4)`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem of finding the ratio of molar volume to the atomic volume of a mole of hydrogen, we can follow these steps: ### Step 1: Understand the Molar Volume The molar volume of an ideal gas at standard temperature and pressure (STP) is given as 22.4 L. We need to convert this volume into cubic meters for our calculations: \[ \text{Molar Volume (Vm)} = 22.4 \, \text{L} = 22.4 \times 10^{-3} \, \text{m}^3 \] ### Step 2: Determine the Size of a Hydrogen Molecule The size of a hydrogen molecule is given as 1 Ångström (1 Å = \(10^{-10}\) m). Therefore, the radius \(r\) of a hydrogen molecule is: \[ r = \frac{1 \, \text{Å}}{2} = 0.5 \, \text{Å} = 0.5 \times 10^{-10} \, \text{m} \] ### Step 3: Calculate the Volume of a Single Hydrogen Atom The volume \(V\) of a single hydrogen atom can be calculated using the formula for the volume of a sphere: \[ V = \frac{4}{3} \pi r^3 \] Substituting the radius: \[ V = \frac{4}{3} \pi (0.5 \times 10^{-10})^3 \] Calculating this: \[ V = \frac{4}{3} \times \frac{22}{7} \times (0.5^3) \times (10^{-30}) = 0.524 \times 10^{-30} \, \text{m}^3 \] ### Step 4: Calculate the Atomic Volume for One Mole of Hydrogen One mole of hydrogen contains Avogadro's number of molecules, which is approximately \(6.023 \times 10^{23}\). Thus, the atomic volume \(V_a\) for one mole of hydrogen is: \[ V_a = 6.023 \times 10^{23} \times 0.524 \times 10^{-30} \] Calculating this: \[ V_a = 3.16 \times 10^{-7} \, \text{m}^3 \] ### Step 5: Calculate the Ratio of Molar Volume to Atomic Volume Now that we have both the molar volume and the atomic volume, we can find the ratio: \[ \text{Ratio} = \frac{V_m}{V_a} = \frac{22.4 \times 10^{-3}}{3.16 \times 10^{-7}} \] Calculating this gives: \[ \text{Ratio} \approx 7.08 \times 10^{4} \] ### Final Answer The ratio of the molar volume to the atomic volume of a mole of hydrogen is approximately \(7.08 \times 10^{4}\). ---
Promotional Banner

Topper's Solved these Questions

  • APPENDICES (REVISION EXERCISE)

    AAKASH SERIES|Exercise MOTION IN A STRAIGHT LINE|59 Videos
  • APPENDICES (REVISION EXERCISE)

    AAKASH SERIES|Exercise MOTION IN A PLANE|87 Videos
  • APPENDICES ( REVISION EXERCISE )

    AAKASH SERIES|Exercise REVISION EXERCISE (MAGNETISM AND MATTER )|52 Videos
  • ATOMS

    AAKASH SERIES|Exercise PRACTICE EXERCISE|21 Videos

Similar Questions

Explore conceptually related problems

The volume of 1 mol of a gas at standard temperature and pressure is .

The ratio of molar volume to ideal molar volume is called .......

The ratio of excluded volume ( b ) to molar volume of a gas molecule is

n moles of an ideal gas at temperature, T (in kelvin) occupy VL of volume, exerting a pressure of P atmospheres. What is the concentration (in mole //L ) ?

Volume of 1.5 mole of a gas at 1 atm. pressure and 273K is

If pressure and temperature of an ideal gas are doubled and volume is halved, the number of molecules of the gas

Volume occupied by an ideal gas at one atmospheric pressure and 0^@C is V ml. Its volume at 273 K will be

One mole of an ideal gas at an initial temperature true of TK does 6R joule of work adiabatically. If the ratio of specific heats of this gas at constant pressure and at constant volume is 5//3 , the final temperature of the gas will be

One mole of an ideal gas at an initial temperature true of TK does 6R joule of work adiabatically. If the ratio of specific heats of this gas at constant pressure and at constant volume is 5//3 , the final temperature of the gas will be

AAKASH SERIES-APPENDICES (REVISION EXERCISE)-LAW OF MOTION
  1. One mole of an ideal gas at standard temperature and pressure occupies...

    Text Solution

    |

  2. A body of mass 1 kg is moving with velocity 30 ms^(-1) due north. It i...

    Text Solution

    |

  3. A force of 20 N acts on a body of mass 5kg at rest. What is the accele...

    Text Solution

    |

  4. A truck starts from rest and accelerates uniformly at 2.0 ms^(-2) . At...

    Text Solution

    |

  5. A particle of mass 70 g, moving at 50 cm/s , is acted upon by a variab...

    Text Solution

    |

  6. A ball of mass 400 gm is dropped from a height of 5m. A boy on the gro...

    Text Solution

    |

  7. A batsman deflects a ball by an angle of 60° without changing its init...

    Text Solution

    |

  8. A body of mass 5 kg is at rest. Three force F(1) = 10 N due North F2=1...

    Text Solution

    |

  9. The momentum of a body in two perpendicular direction at any time 't' ...

    Text Solution

    |

  10. A bullet is fired from a gun. The force on the bullet is given by F=60...

    Text Solution

    |

  11. A body of mass 5kg starts from the origin with an initial velocity of...

    Text Solution

    |

  12. A 15Kg mass is accelerated from rest with a force of 100N. As it moves...

    Text Solution

    |

  13. A cart loaded with sand moves along a horizontal floor due to a consta...

    Text Solution

    |

  14. Two billiard balls each of mass 0.05 kg moving in opposite direction w...

    Text Solution

    |

  15. Figure 5.17 shows the position-time graph of a body of mass 0.04 kg . ...

    Text Solution

    |

  16. The driver of a three-wheeler moving with a speed of 36 km/h sees a ch...

    Text Solution

    |

  17. If the average velocity of a body moving with uniform acceleration und...

    Text Solution

    |

  18. Five persons A, B, C, D & E are pulling a cart of mass 100kg on a smoo...

    Text Solution

    |

  19. A box is put on a scale which is adjusted to read zero, when the box i...

    Text Solution

    |

  20. Two masses each equal to m are lying on x-axis at (-a,0)(+a,0) respect...

    Text Solution

    |

  21. Water is flowing at a speed of 1.5ms^(-1) through a horizontal tube of...

    Text Solution

    |