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A stone is dropeed from a height of10 cm...

A stone is dropeed from a height of10 cm above the top of a window 80 cm high. The time taken by the stone to cross the window is `(g = 9.8 ms^(-2))`

A

`1/7 s`

B

`3/7 s`

C

`2/7 s`

D

`4/7 s`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem of finding the time taken by a stone to cross a window when dropped from a height of 10 cm above the top of the window (which is 80 cm high), we can follow these steps: ### Step-by-Step Solution: 1. **Understand the Problem**: - The stone is dropped from a height of 10 cm above the top of an 80 cm high window. - Therefore, the total distance the stone falls before it crosses the window is 10 cm + 80 cm = 90 cm. 2. **Convert Units**: - Convert the distances from centimeters to meters: - Height above the window = 10 cm = 0.10 m - Height of the window = 80 cm = 0.80 m - Total distance fallen = 90 cm = 0.90 m 3. **Calculate Time to Fall 10 cm (T1)**: - Use the kinematic equation: \[ s = ut + \frac{1}{2}gt^2 \] where \(s\) is the distance fallen (0.10 m), \(u\) is the initial velocity (0 m/s), \(g\) is the acceleration due to gravity (9.8 m/s²), and \(t\) is the time taken (T1). - Plugging in the values: \[ 0.10 = 0 + \frac{1}{2} \times 9.8 \times T1^2 \] - Rearranging gives: \[ T1^2 = \frac{0.10 \times 2}{9.8} \] \[ T1^2 = \frac{0.20}{9.8} \approx 0.02041 \] - Taking the square root: \[ T1 \approx \sqrt{0.02041} \approx 0.1429 \text{ seconds} \approx \frac{1}{7} \text{ seconds} \] 4. **Calculate Time to Fall 90 cm (T)**: - Using the same kinematic equation for the total distance of 0.90 m: \[ 0.90 = 0 + \frac{1}{2} \times 9.8 \times T^2 \] - Rearranging gives: \[ T^2 = \frac{0.90 \times 2}{9.8} \] \[ T^2 = \frac{1.80}{9.8} \approx 0.18367 \] - Taking the square root: \[ T \approx \sqrt{0.18367} \approx 0.428 \text{ seconds} \approx \frac{3}{7} \text{ seconds} \] 5. **Calculate Time Taken to Cross the Window**: - The time taken to cross the window is given by: \[ \text{Time to cross window} = T - T1 \] - Substituting the values: \[ \text{Time to cross window} = \frac{3}{7} - \frac{1}{7} = \frac{2}{7} \text{ seconds} \] ### Final Answer: The time taken by the stone to cross the window is \(\frac{2}{7}\) seconds.
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