A particle moves in a circular path such that its speed v varies with distance s as `v=alphasqrt(s)` where `alpha` is a positive constant. If the acceleration of the particle after traversing a distance s is `[alpha^2sqrt(x+s^2/R^2)]` find x.

Options

A. `alpha sqrt(1/4 - (S^2)/(R^2))`
B. `alpha sqrt(1/4 + (S^2)/(R^2))`
C. `alpha sqrt(1/2 + (S^2)/(R^2))`
D. `alpha^2 sqrt(1/2 + (S^2)/(R^2))`

Answer

B