Two particles of mases `m_(1)` and `m_(2)` in projectile motion have velocitie `vecv_(1)` and `vecv_(2)`, respectively at time `t=0`. they collide at time `t_(0)`. Their velocities become `vecv_(1)^(')` and `vecv_(2)^(')` at time `2t_(0)` while still moving in air. The value of
`|(m_(1)vecv_(1)^(')+m_(2)vecv_(2)^('))|-|(m_(1)vecv_(1)+m_(2)vecv_(2))|` is

Options

A. zero
B. `(m_1 + m_2) g t_0`
C. `2(m_1 + m_2)g t_0`
D. `1/2 (m_1 + m_2) g t_0`

Answer

C