A homogeneous rod of length L is acted upon by two forces `F_(1) and F_(2)` applied to its ends and directed opposite to each other. With what force F will the rod be stretched at the cross section at a distance l from the end where `F_(1)` is applied?

Options

A. `((F_2 - F_1)l)/(L)`
B. `((F_2 - F_1)l)/(L) + F_1`
C. `((F_2 + F_1)l)/(2L)`
D. `((F_2^2 - F_1^2)l)/(L)`

Answer

B