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A 40 kg slab rests on a frictionless flo...

A 40 kg slab rests on a frictionless floor. A 10 kg block rests on top of the slab. The coefficient of friction between the block and the slab is 0.40. The 10 kg block is acted upon by a horizontal force of 100 N. If `g=10m//s^(2)`, the resulting acceleration of the slab will be

A

`0.98 ms^(-2)`

B

`1.47 ms^(-2)`

C

`1.52 ms^(-2)`

D

`6.1 ms^(2)`

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The correct Answer is:
A
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AAKASH SERIES-APPENDICES (REVISION EXERCISE)-LAW OF MOTION
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