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A constant force actson a body of mass m...

A constant force actson a body of mass m, at rest and produces a velocity 'v' over a displacement '`s_1`'. The same force acts on another body of mass `m_2` at rest and produces the same velocity. 'v' over a displacement '`s_2`'. The ratio of the displacements is

A

`m_1 : m_2`

B

`m_2 : m_1`

C

`sqrt(m_1) : sqrt(m_2)`

D

`sqrt(m_2) : sqrt(m_1)`

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AI Generated Solution

The correct Answer is:
To solve the problem, we need to analyze the motion of two bodies under the influence of the same constant force. Here's the step-by-step solution: ### Step 1: Understand the given information We have two bodies: - Body 1 with mass \( m_1 = m \) (mass of the first body) - Body 2 with mass \( m_2 \) Both bodies start from rest and reach the same final velocity \( v \) over different displacements \( s_1 \) and \( s_2 \) respectively. ### Step 2: Apply the third equation of motion The third equation of motion relates initial velocity, final velocity, acceleration, and displacement: \[ v^2 = u^2 + 2as \] Since both bodies start from rest, the initial velocity \( u = 0 \). Thus, the equation simplifies to: \[ v^2 = 2as \] Where \( a \) is the acceleration and \( s \) is the displacement. ### Step 3: Express acceleration in terms of force and mass From Newton's second law, we know that: \[ F = ma \] Thus, the acceleration \( a \) can be expressed as: \[ a = \frac{F}{m} \] ### Step 4: Substitute acceleration into the equation Substituting \( a \) into the equation \( v^2 = 2as \): \[ v^2 = 2 \left(\frac{F}{m}\right) s \] Rearranging gives: \[ s = \frac{mv^2}{2F} \] ### Step 5: Write the equations for both bodies For body 1 (mass \( m_1 = m \)): \[ s_1 = \frac{mv^2}{2F} \] For body 2 (mass \( m_2 \)): \[ s_2 = \frac{m_2v^2}{2F} \] ### Step 6: Find the ratio of displacements Now we can find the ratio of the displacements \( \frac{s_1}{s_2} \): \[ \frac{s_1}{s_2} = \frac{\frac{mv^2}{2F}}{\frac{m_2v^2}{2F}} = \frac{m}{m_2} \] Thus, the ratio of the displacements is: \[ \frac{s_1}{s_2} = \frac{m}{m_2} \] ### Final Answer The ratio of the displacements \( s_1 \) and \( s_2 \) is \( \frac{m}{m_2} \). ---
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