The value of escape speed from the surfa...

The value of escape speed from the surface of earth is

34.02

34.48

18.42

20.15

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Mass and radius of a planet are two times the value of earth. What is the value of escape velocity from the surface of this planet?

Two escape speed from the surface of earth is V_(e) . The escape speed from the surface of a planet whose mass and radius are double that of earth will be.

If a body is projected with speed v greater than escape speed v_(e) from the surface of earth, find its speed in intersteller space.

An artificial satellite is moving in circular orbit around the earth with speed equal to half the magnitude of escape velocity from the surface of earth. R is the radius of earth and g is acceleration due to gravity at the surface of earth (R = 6400km) Then the distance of satelite from the surface of earth is .

A rocket is fired with a speed v = 2 sqrt (gR) near the earth's surface and directed upward, what is intersteller speed of rocket v^' , where v_e escape speed on the surface of earth

The escape velocity from the surface of the earth is V_(e) . The escape velcotiy from the surface of a planet whose mass and radius are three times those of the earth, will be

The escape velocity from the surface of the earth is (where R_(E) is the radius of the earth )

The escape velocity of a body from the surface of the earth is equal to

The escape velocity of a particle of a particle from the surface of the earth is given by

Gravitational acceleration on the surface of a planet is (sqrt6)/(11)g. where g is the gravitational acceleration on the surface of the earth. The average mass density of the planet is (2)/(3) times that of the earth. If the escape speed on the surface of the earht is taken to be 11 kms^(-1) the escape speed on the surface of the planet in kms^(-1) will be

AAKASH SERIES-LAWS OF MOTION-PRACTICE EXERCISE

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