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The displacement of x of a particle at t...

The displacement of x of a particle at the instant when its velocity v is given by `v=sqrt(3x +16)`. Find its acceleration and initial velocity.

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The correct Answer is:
1
`v=sqrt(3x+16)` or `v^(2)=3x+16`
or `v^(2)-16=3x` Comparing with `v^(2)-u^(2)=2as`,
we get ,u=4 units ,2a=3 or a=1.5 units
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