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A body starts from rest and moves with u...

A body starts from rest and moves with uniform acceleration of `5ms^(-2)` for 8 seconds. From that times the acceleration ceases. Find the distance covered in 12s starting from rest.

Text Solution

Verified by Experts

The velocity after 8 seconds
v=0+`5xx8`=40 m/s
Distance covered in 8 seconds
`S_(0)=0+(1)/(2)xx5xx64=160m`
After 8s the body with uniform velocity and distance covered in 4s with uniform velocity is
S=vt=`40xx4`=160 m
The distance covered in
12s =160+160=320 m.
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