Home
Class 12
PHYSICS
A bus starting from rest, accelerates at...

A bus starting from rest, accelerates at the rate of f through a distance S, then continues at constant speed for time t and declerates at the rate f/2 to come to rest. If the total distance travelled is 15 S then S =

Text Solution

Verified by Experts


`AB=S(1)/(2)ft_(1)^(2)`………(1)
`v=ft_(1)`
BC=vt= `(ft_(1))t` ……….(2)
`CD=(u^(2))/(2a)=((ft_(1))^(2))/(2(f//2))=2S`………..(3)
S+`ft_(1)t+2S=15S`
`ft_(1)t=12S`--------(4)
Dividing (4) by (1) `t_(1)=(t)/(6)`
Now (1) gives S `(1)/(2)f(t^(2))/(36)`
`thereforS=(ft^(2))/(72)`
Promotional Banner

Similar Questions

Explore conceptually related problems

A car, starting from rest, accelerates at the rate f through a distance s, then continues at constant speed for time t and then decelerates at the rate f/ 2 to come to rest. If the total distance travelled is 15 s, then

A car, starting from rest, accelerates at the rate f through a distance s, then continues at constant speed for time t and then decelerates at the rate f/ 2 to come to rest. If the total distance travelled is 15 s, then

A car , starting from rest, accelerates at the rate f through a distance S then continues at constant speed for time t and then decelerates at the rate (f)/(2) to come to rest . If the total distance traversed is 15 S , then

A car, starting from rest, accelerates at the rate (f) through a distance (S), then continues at constant speed for some time (t) and then decelerates at the rate f//2 to come to rest. If the total distance is 5 S , then prove that S=1/2/ ft^(2) .

A particle starts from rest accelerates at 2 m//s^2 for 10 s and then goes for constant speed for 30 s and then decelerates at 4 m//s^2 till it stops. What is the distance travelled by it.

A particle starts from rest, accelerates at 2(m)/(s^2) for 10 s and then goes for constant speed for 30 s and then decelerates at 4(m)/(s^2) . Till it stops. What is the distance travelled by it?

A body starts from rest, what is the ratio of the distance travelled by the body during the 4th and 3rd s?

A body starts from rest and accelerates with 4 "m/s"^2 for 5 seconds. Find the distance travelled with 5 seconds.

A train starts from rest and accelerates uniformly at a rate of 2 m s^(-2) for 10 s. It then maintains a constant speed for 200 s. The brakes are then applied and the train is uniformly retarded and comes to rest in 50 s. Find : (i) the maximum velocity reached, (ii) the retardation in the last 50 S, (iii) the total distance travelled, and (iv) the average velocity of the train.

A car starts moving on a straight road. It makes the entire journey in three parts. The total time of journey is 25 s. For first part it accelerates at a constant rate 5m//s^(2) . For second part it moves with a constant speed. For the third part it retards at constant rate 5m//s^(2) to come to rest. If the average speed for entire journey is 20 m/s, time period of first part of journey is