solve `x^3-7x^2+36=0` given one root being twice the other .

solve x^3-7x^2+14x-8=0 given that the roots are in geometric progression.

Solve the equation x^3-13 x^2+15 x+189=0 if one root exceeds the other by 2.

In the equation x^(2)+kx+54=0 , one root is twice the other root. The value(s) of k is (are)

Solve 18x^3+81x^2+121x+60=0 given that one roots is equal to half the sum of the remainging roots .

solve x^3 -9x^2 + 14x+ 24 =0 given that two of the roots are in the ratio 3:2

The quadratic equations x^(2)-6x+a=0 and x^(2)-cx+6=0 have one root in common. The other roots of the first and second equations are integers in the ratio 4:3. then the common root is

Solve the equation x^3 -x^2 +3x +5=0 one root being 1-2i.

Solve x ^2−5x−36=0.

Solve x^(2)-7x+6 gt 0 .

Solve the equation x^3 -6x^2 +7x +2=0 one root being 2 + sqrt(5)