solve `x^3-7x^2+14x-8=0` given that the roots are in geometric progression.

solve x^3 -9x^2 + 14x+ 24 =0 given that two of the roots are in the ratio 3:2

Solve 4x^3-24x^2+23x+18=0 ,givne that the roots of this equation are in arithmetic progression

Solve 9x^3-15x^2+7x-1=0 , given that two of its roots are equal .

If the roots of the equation x^(3) - 7x^(2) + 14x - 8 = 0 are in geometric progression, then the difference between the largest and the smallest roots is

solve x^3-7x^2+36=0 given one root being twice the other .

If the roots of the equation x^3 +3px^2 + 3qx -8=0 are in a geometric progression , then (q^3)/( p^3) =

Solve 8x^4 -2x^3 - 27 x^2 +6x +9=0 given that two roots have the same absolute value , but are opposite in sign.

Let alpha, beta and gamma are the roots of the equation 2x^(2)+9x^(2)-27x-54=0 . If alpha, beta, gamma are in geometric progression, then the value of |alpha|+|beta|+|gamma|=

Solve x^4 +x^3- 16x^2 -4x + 48 =0 given that the product of two of the roots is 6.

If the roots of x^(3) - 42x^(2) + 336x - 512 = 0 , are in increasing geometric progression, its common ratio is