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If product of two roots of 4x^3 + ...

If product of two roots of ` 4x^3 + 16 x^2 +kx - 36 =0` is -6 then k=

A

9

B

`-9`

C

`8`

D

`-8`

Text Solution

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The correct Answer is:
To solve the problem, we need to find the value of \( k \) in the cubic equation \( 4x^3 + 16x^2 + kx - 36 = 0 \) given that the product of two of its roots is -6. ### Step-by-Step Solution: 1. **Identify the Roots**: Let the roots of the equation be \( \alpha, \beta, \gamma \). According to the problem, we know that: \[ \alpha \beta = -6 \] 2. **Use Vieta's Formulas**: From Vieta's formulas for a cubic equation \( ax^3 + bx^2 + cx + d = 0 \): - The sum of the roots \( \alpha + \beta + \gamma = -\frac{b}{a} = -\frac{16}{4} = -4 \) (Equation 1) - The sum of the product of the roots taken two at a time \( \alpha \beta + \beta \gamma + \gamma \alpha = \frac{c}{a} = \frac{k}{4} \) (Equation 2) - The product of the roots \( \alpha \beta \gamma = -\frac{d}{a} = -\frac{-36}{4} = 9 \) (Equation 3) 3. **Substituting the Known Product**: From Equation 3, we have: \[ \alpha \beta \gamma = 9 \] Since \( \alpha \beta = -6 \), we can express \( \gamma \) as: \[ \gamma = \frac{9}{\alpha \beta} = \frac{9}{-6} = -\frac{3}{2} \] 4. **Finding \( \alpha + \beta \)**: Using Equation 1: \[ \alpha + \beta + \gamma = -4 \] Substituting \( \gamma = -\frac{3}{2} \): \[ \alpha + \beta - \frac{3}{2} = -4 \] Rearranging gives: \[ \alpha + \beta = -4 + \frac{3}{2} = -\frac{8}{2} + \frac{3}{2} = -\frac{5}{2} \] 5. **Substituting into Equation 2**: Now we substitute \( \alpha \beta = -6 \) and \( \alpha + \beta = -\frac{5}{2} \) into Equation 2: \[ \alpha \beta + \beta \gamma + \gamma \alpha = \frac{k}{4} \] Substituting the known values: \[ -6 + \gamma(\alpha + \beta) = \frac{k}{4} \] Substituting \( \gamma = -\frac{3}{2} \) and \( \alpha + \beta = -\frac{5}{2} \): \[ -6 + \left(-\frac{3}{2}\right)\left(-\frac{5}{2}\right) = \frac{k}{4} \] Calculating \( \left(-\frac{3}{2}\right)\left(-\frac{5}{2}\right) = \frac{15}{4} \): \[ -6 + \frac{15}{4} = \frac{k}{4} \] Converting -6 to a fraction: \[ -6 = -\frac{24}{4} \] Thus: \[ -\frac{24}{4} + \frac{15}{4} = \frac{k}{4} \] Simplifying gives: \[ -\frac{9}{4} = \frac{k}{4} \] Multiplying both sides by 4: \[ k = -9 \] ### Final Answer: Thus, the value of \( k \) is \( \boxed{-9} \).
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