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Find the roots of x^2+3x-4=0 is...

Find the roots of `x^2+3x-4=0` is

A

`1,-4`

B

`3,7`

C

`-1,4`

D

`-5,2`

Text Solution

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The correct Answer is:
To find the roots of the quadratic equation \( x^2 + 3x - 4 = 0 \), we can use the factorization method. Here are the steps: ### Step 1: Write the equation We start with the equation: \[ x^2 + 3x - 4 = 0 \] ### Step 2: Factor the quadratic We need to factor the quadratic expression. We look for two numbers that multiply to \(-4\) (the constant term) and add to \(3\) (the coefficient of \(x\)). The numbers that satisfy these conditions are \(4\) and \(-1\). Thus, we can rewrite the equation as: \[ x^2 + 4x - 1x - 4 = 0 \] ### Step 3: Group the terms Now, we group the terms: \[ (x^2 + 4x) + (-1x - 4) = 0 \] ### Step 4: Factor by grouping Next, we factor out the common terms in each group: \[ x(x + 4) - 1(x + 4) = 0 \] ### Step 5: Factor out the common binomial Now we can factor out the common binomial \((x + 4)\): \[ (x + 4)(x - 1) = 0 \] ### Step 6: Set each factor to zero Now, we set each factor equal to zero: 1. \(x + 4 = 0\) 2. \(x - 1 = 0\) ### Step 7: Solve for \(x\) Solving these equations gives us: 1. \(x = -4\) 2. \(x = 1\) ### Conclusion Thus, the roots of the equation \(x^2 + 3x - 4 = 0\) are: \[ x = 1 \quad \text{and} \quad x = -4 \]
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