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The roots of 48x^3 - 44 x^2 + 12 x -1=...

The roots of ` 48x^3 - 44 x^2 + 12 x -1=0` are in

A

A.P

B

G.P

C

H.P

D

A.G.P

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To solve the equation \( 48x^3 - 44x^2 + 12x - 1 = 0 \) and find the roots, we will follow these steps: ### Step 1: Use the Rational Root Theorem We will start by testing possible rational roots of the polynomial. A good candidate to test is \( x = \frac{1}{2} \). ### Step 2: Substitute \( x = \frac{1}{2} \) into the equation Substituting \( x = \frac{1}{2} \): \[ 48\left(\frac{1}{2}\right)^3 - 44\left(\frac{1}{2}\right)^2 + 12\left(\frac{1}{2}\right) - 1 \] Calculating each term: \[ = 48 \cdot \frac{1}{8} - 44 \cdot \frac{1}{4} + 12 \cdot \frac{1}{2} - 1 \] \[ = 6 - 11 + 6 - 1 = 0 \] Since the result is 0, \( x = \frac{1}{2} \) is a root. ### Step 3: Polynomial Division Now we will divide the polynomial \( 48x^3 - 44x^2 + 12x - 1 \) by \( x - \frac{1}{2} \) using synthetic or polynomial long division. To perform polynomial long division: 1. Multiply \( x - \frac{1}{2} \) by \( 48x^2 \) to get \( 48x^3 - 24x^2 \). 2. Subtract this from the original polynomial: \[ (48x^3 - 44x^2 + 12x - 1) - (48x^3 - 24x^2) = -20x^2 + 12x - 1 \] 3. Next, multiply \( x - \frac{1}{2} \) by \( -20x \) to get \( -20x^2 + 10x \). 4. Subtract again: \[ (-20x^2 + 12x - 1) - (-20x^2 + 10x) = 2x - 1 \] 5. Finally, multiply \( x - \frac{1}{2} \) by \( 2 \) to get \( 2x - 1 \). 6. Subtract: \[ (2x - 1) - (2x - 1) = 0 \] The result of the division is \( 48x^2 - 20x + 2 \). ### Step 4: Solve the Quadratic Equation Now we solve the quadratic equation \( 48x^2 - 20x + 2 = 0 \) using the quadratic formula: \[ x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} \] Where \( a = 48, b = -20, c = 2 \): \[ x = \frac{20 \pm \sqrt{(-20)^2 - 4 \cdot 48 \cdot 2}}{2 \cdot 48} \] \[ = \frac{20 \pm \sqrt{400 - 384}}{96} \] \[ = \frac{20 \pm \sqrt{16}}{96} \] \[ = \frac{20 \pm 4}{96} \] Calculating the two possible values: 1. \( x = \frac{24}{96} = \frac{1}{4} \) 2. \( x = \frac{16}{96} = \frac{1}{6} \) ### Step 5: List the Roots The roots of the original polynomial are: \[ x = \frac{1}{2}, \quad x = \frac{1}{4}, \quad x = \frac{1}{6} \] ### Step 6: Check if the Roots are in Harmonic Progression (HP) To check if these roots are in HP, we take their reciprocals: - \( \frac{1}{\frac{1}{2}} = 2 \) - \( \frac{1}{\frac{1}{4}} = 4 \) - \( \frac{1}{\frac{1}{6}} = 6 \) The sequence \( 2, 4, 6 \) is an arithmetic progression (AP), which means that the original roots are in HP. ### Conclusion The roots of the equation \( 48x^3 - 44x^2 + 12x - 1 = 0 \) are \( \frac{1}{2}, \frac{1}{4}, \frac{1}{6} \) and they are in HP. ---
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