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If there is a multiple root of orde...

If there is a multiple root of order 3 for the equation `x^4 - 2x ^3 + 2x -a=0` then the other root is

A

`-1`

B

`0`

C

1

D

2

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we need to find the other root of the polynomial equation given that there is a multiple root of order 3. Let's denote the multiple root as \( \alpha \) and the other root as \( \beta \). The equation is: \[ x^4 - 2x^3 + 2x - a = 0 \] ### Step 1: Understanding the Roots Since there is a multiple root of order 3, we can express the roots as \( \alpha, \alpha, \alpha, \beta \). ### Step 2: Using Vieta's Formulas According to Vieta's formulas, the sum of the roots of the polynomial \( x^4 + bx^3 + cx^2 + dx + e = 0 \) is given by: \[ \text{Sum of roots} = -\frac{\text{coefficient of } x^3}{\text{coefficient of } x^4} = -(-2) = 2 \] This means: \[ 3\alpha + \beta = 2 \tag{1} \] ### Step 3: Sum of the Products of Roots Taken Two at a Time The sum of the products of the roots taken two at a time is given by: \[ \text{Sum of products of roots} = \frac{\text{coefficient of } x^2}{\text{coefficient of } x^4} = 0 \] This means: \[ \alpha^2 + \alpha^2 + \alpha^2 + 3\alpha\beta = 0 \] Simplifying gives: \[ 3\alpha^2 + 3\alpha\beta = 0 \] Dividing by 3, we have: \[ \alpha^2 + \alpha\beta = 0 \tag{2} \] ### Step 4: Solving the Equations From equation (2), we can factor out \( \alpha \): \[ \alpha(\alpha + \beta) = 0 \] This gives us two cases: 1. \( \alpha = 0 \) 2. \( \alpha + \beta = 0 \) #### Case 1: \( \alpha = 0 \) If \( \alpha = 0 \), substituting into equation (1): \[ 3(0) + \beta = 2 \implies \beta = 2 \] #### Case 2: \( \alpha + \beta = 0 \) If \( \alpha + \beta = 0 \), then \( \beta = -\alpha \). Substituting into equation (1): \[ 3\alpha - \alpha = 2 \implies 2\alpha = 2 \implies \alpha = 1 \] Thus, \( \beta = -1 \). ### Conclusion The possible values for the other root \( \beta \) are: 1. \( \beta = 2 \) when \( \alpha = 0 \) 2. \( \beta = -1 \) when \( \alpha = 1 \) Therefore, the other root can be either \( 2 \) or \( -1 \). ### Final Answer The other root is \( \beta = 2 \) or \( \beta = -1 \). ---
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