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solve x^2 -3x +2=0...

solve` x^2 -3x +2=0`

A

`-1`

B

1

C

2

D

3

Text Solution

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The correct Answer is:
To solve the quadratic equation \( x^2 - 3x + 2 = 0 \), we can follow these steps: ### Step 1: Write the equation We start with the given equation: \[ x^2 - 3x + 2 = 0 \] ### Step 2: Factor the quadratic expression We need to factor the quadratic expression. We look for two numbers that multiply to \( +2 \) (the constant term) and add up to \( -3 \) (the coefficient of \( x \)). The numbers that satisfy these conditions are \( -1 \) and \( -2 \). Thus, we can rewrite the equation as: \[ x^2 - 2x - x + 2 = 0 \] ### Step 3: Group the terms Next, we group the terms: \[ (x^2 - 2x) + (-x + 2) = 0 \] ### Step 4: Factor by grouping Now we factor out the common terms from each group: \[ x(x - 2) - 1(x - 2) = 0 \] ### Step 5: Factor out the common binomial We can factor out the common binomial \( (x - 2) \): \[ (x - 2)(x - 1) = 0 \] ### Step 6: Set each factor to zero Now, we set each factor equal to zero: 1. \( x - 2 = 0 \) → \( x = 2 \) 2. \( x - 1 = 0 \) → \( x = 1 \) ### Step 7: Write the final solutions The solutions to the equation \( x^2 - 3x + 2 = 0 \) are: \[ x = 2 \quad \text{and} \quad x = 1 \]
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