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Assertion (A) : If alpha , beta, gamma...

Assertion (A) : If ` alpha , beta, gamma ` are the roots of ` x^3 -x-1=0` then ` alpha^3 + beta^3 + gamma^3 =1`
Reason (R ): If a +b+c=0 then ` a^3 + b^3 +c^3 = 3abc`

A

both A and R are true R is the correct explanation of A

B

both A and R are true and R is not correct explanation of A

C

A is true and R is false

D

A is false and R is true

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we need to analyze both the assertion and the reason provided. ### Step 1: Analyze the Assertion The assertion states that if \( \alpha, \beta, \gamma \) are the roots of the polynomial \( x^3 - x - 1 = 0 \), then: \[ \alpha^3 + \beta^3 + \gamma^3 = 1 \] ### Step 2: Find the Sum of the Roots Using Vieta's formulas, we know that for a cubic equation of the form \( x^3 + px^2 + qx + r = 0 \): - The sum of the roots \( \alpha + \beta + \gamma = -p \) In our equation \( x^3 - x - 1 = 0 \), there is no \( x^2 \) term, so: \[ \alpha + \beta + \gamma = 0 \] ### Step 3: Use the Identity for the Sum of Cubes We can use the identity for the sum of cubes: \[ \alpha^3 + \beta^3 + \gamma^3 - 3\alpha\beta\gamma = (\alpha + \beta + \gamma)(\alpha^2 + \beta^2 + \gamma^2 - \alpha\beta - \beta\gamma - \gamma\alpha) \] Since \( \alpha + \beta + \gamma = 0 \), we can simplify this to: \[ \alpha^3 + \beta^3 + \gamma^3 = 3\alpha\beta\gamma \] ### Step 4: Find the Product of the Roots Again using Vieta's formulas, the product of the roots \( \alpha \beta \gamma \) is given by: \[ \alpha \beta \gamma = -\frac{r}{1} = -(-1) = 1 \] ### Step 5: Substitute the Product into the Identity Now substituting \( \alpha \beta \gamma = 1 \) into the identity we derived: \[ \alpha^3 + \beta^3 + \gamma^3 = 3 \cdot 1 = 3 \] ### Step 6: Conclusion on the Assertion Thus, we find that: \[ \alpha^3 + \beta^3 + \gamma^3 = 3 \] This contradicts the assertion that \( \alpha^3 + \beta^3 + \gamma^3 = 1 \). Therefore, the assertion is false. ### Step 7: Analyze the Reason The reason states that if \( a + b + c = 0 \), then: \[ a^3 + b^3 + c^3 = 3abc \] This is indeed true, as we derived this from the identity above. ### Final Conclusion - Assertion (A) is **false**. - Reason (R) is **true**.
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