Home
Class 12
MATHS
The equation 6x ^5 + 7x^4 +12x^3+ 1...

The equation ` 6x ^5 + 7x^4 +12x^3+ 12x^2 + 7x +6=0` is a reciprocal equation of

A

class one and odd order

B

class two and odd order

C

class one and even order

D

Class two and even order

Text Solution

AI Generated Solution

The correct Answer is:
To determine the class and order of the given equation \( 6x^5 + 7x^4 + 12x^3 + 12x^2 + 7x + 6 = 0 \), we will analyze the coefficients of the polynomial. ### Step 1: Identify the coefficients of the polynomial The given polynomial is: \[ 6x^5 + 7x^4 + 12x^3 + 12x^2 + 7x + 6 \] The coefficients are: - Coefficient of \( x^5 \): 6 - Coefficient of \( x^4 \): 7 - Coefficient of \( x^3 \): 12 - Coefficient of \( x^2 \): 12 - Coefficient of \( x^1 \): 7 - Constant term (coefficient of \( x^0 \)): 6 ### Step 2: Check for reciprocal properties For a polynomial to be classified as a reciprocal polynomial, the coefficients must satisfy the following conditions: - The coefficient of \( x^n \) (where \( n \) is the degree of the polynomial) must be equal to the constant term. - The coefficient of \( x^{n-1} \) must be equal to the coefficient of \( x^1 \). - The coefficient of \( x^{n-2} \) must be equal to the coefficient of \( x^2 \). - And so on... Let's check these conditions: - Coefficient of \( x^5 \) (6) is equal to the constant term (6). - Coefficient of \( x^4 \) (7) is equal to the coefficient of \( x^1 \) (7). - Coefficient of \( x^3 \) (12) is equal to the coefficient of \( x^2 \) (12). Since all these conditions are satisfied, the polynomial is indeed a reciprocal polynomial. ### Step 3: Determine the class and order Next, we need to determine the class and order of the polynomial: - **Class**: The polynomial is of class 1 because the coefficients match as described above. - **Order**: The polynomial has no middle term (the term \( x^3 \) and \( x^2 \) are present but are equal), which indicates that it is of even order. ### Conclusion Thus, the given polynomial \( 6x^5 + 7x^4 + 12x^3 + 12x^2 + 7x + 6 = 0 \) is a reciprocal equation of **class 1 and even order**. ### Final Answer The correct option is: **Class 1 and Even Order**. ---
Promotional Banner

Similar Questions

Explore conceptually related problems

Solve the equation x^2 -7x +12 =0

Solve the following equations 2x^5+x^4-12x^3-12x^2+x+2=0

If 2,3 are two roots of the reciprocal equation 6x^5 - 29 x^4 +2x^3 +2x^2 -29 x+6=0 then the other roots are

Assertion (A ) : the number of roots of x^4 +2x^3 -7x^2 -8x +12=0 Reason (R ) : Every algebraic equation of degree n has n roots and nomore .

The repeated root of the equation 4x^3 -12x^2 -15x -4=0 is

If the roots of the equation 4x^3 -12x^2 +11x +k=0 are in arithmetic progression then k=

Is {x : x^(2) - 7x + 12=0} = {3,4} ?

The function f : [0, 7] to [0, 70] where f(x) = x^(3) - 12x^(2) + 45x , is

The two circles x^2 + y^2 -2x+6y+6=0 and x^2 + y^2 - 5x + 6y + 15 = 0 touch eachother. The equation of their common tangent is : (A) x=3 (B) y=6 (C) 7x-12y-21=0 (D) 7x+12y+21=0

Solve the equation 12x^4-56 x^3+89 x^2-56 x+12=0.