Find the roots of the equation 3x^2+6x+3...

Find the roots of the equation `3x^2+6x+3=0`

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The correct Answer is:

`:. (x^(3))/((x-a)(x-b)(x-c))= 1 + (a^(3))/((a-b)(a-c)(x-a))+(b^(3))/((b-a)(b-c)(x-b))+(c^(3))/((c-a)(c-b)(x-c))`

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