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Resolve the following into partial fract...

Resolve the following into partial fractions.
`(x^(2)-3)/((x-2)(x^(2)+1))`

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To resolve the expression \(\frac{x^2 - 3}{(x - 2)(x^2 + 1)}\) into partial fractions, we follow these steps: ### Step 1: Set Up the Partial Fraction Decomposition We can express the given fraction as: \[ \frac{x^2 - 3}{(x - 2)(x^2 + 1)} = \frac{A}{x - 2} + \frac{Bx + C}{x^2 + 1} \] where \(A\), \(B\), and \(C\) are constants that we need to determine. ### Step 2: Clear the Denominator Multiply both sides by the denominator \((x - 2)(x^2 + 1)\) to eliminate the fraction: \[ x^2 - 3 = A(x^2 + 1) + (Bx + C)(x - 2) \] ### Step 3: Expand the Right Side Now, we expand the right side: \[ x^2 - 3 = A(x^2 + 1) + Bx(x - 2) + C(x - 2) \] \[ = Ax^2 + A + Bx^2 - 2Bx + Cx - 2C \] Combine like terms: \[ = (A + B)x^2 + (-2B + C)x + (A - 2C) \] ### Step 4: Equate Coefficients Now, we equate the coefficients from both sides of the equation: 1. Coefficient of \(x^2\): \(A + B = 1\) 2. Coefficient of \(x\): \(-2B + C = 0\) 3. Constant term: \(A - 2C = -3\) ### Step 5: Solve the System of Equations From the first equation, we can express \(A\) in terms of \(B\): \[ A = 1 - B \] Substituting \(A\) into the third equation: \[ (1 - B) - 2C = -3 \] This simplifies to: \[ 1 - B - 2C = -3 \implies -B - 2C = -4 \implies B + 2C = 4 \quad \text{(Equation 4)} \] Now we have two equations: 1. \( -2B + C = 0 \quad \text{(Equation 2)} \) 2. \( B + 2C = 4 \quad \text{(Equation 4)} \) From Equation 2, we can express \(C\) in terms of \(B\): \[ C = 2B \] Substituting \(C\) into Equation 4: \[ B + 2(2B) = 4 \implies B + 4B = 4 \implies 5B = 4 \implies B = \frac{4}{5} \] Now substituting back to find \(C\): \[ C = 2B = 2 \cdot \frac{4}{5} = \frac{8}{5} \] Now substituting \(B\) back to find \(A\): \[ A = 1 - B = 1 - \frac{4}{5} = \frac{1}{5} \] ### Step 6: Write the Partial Fraction Decomposition Now we can write the partial fraction decomposition: \[ \frac{x^2 - 3}{(x - 2)(x^2 + 1)} = \frac{1/5}{x - 2} + \frac{(4/5)x + (8/5)}{x^2 + 1} \] ### Step 7: Final Expression Thus, the final expression in partial fractions is: \[ \frac{1}{5(x - 2)} + \frac{4x + 8}{5(x^2 + 1)} \]
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