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Calculate the resonance enegry of NO(2) ...

Calculate the resonance enegry of `NO_(2) ( :O-N=O: )`
The measured enthalpy formation of `NO_(2)(Delta_(f)H^(Theta))` is `34 kJ mol^(-1)`. The bond energies given are:
`N -O rArr 222 kJ mol^(-1)`
`N -= N rArr 946 kJ mol^(-1)`
`O = O rArr 498 kJ mol^(-1)`
`N = O rArr 607 kJ mol^(-1)`

A

`- (1)/(4x)+(1)/(2x^(2))+(1)/(4(x+2))`

B

`(1)/(4x)+(1)/(2x^(2))+(1)/(4(x+2))`

C

`- (1)/(4x)+(1)/(x^(2))+(1)/(4(x+2))`

D

`(1)/(4x)-(1)/(2x^(2))+(1)/(4(x+2))`

Text Solution

Verified by Experts

The correct Answer is:
A
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