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If |x|lt 1, tnen the coefficient of x^(5...

If `|x|lt 1`, tnen the coefficient of `x^(5)` in the expansion of `(1-x)log_(e )(1-x)` is

A

`(1)/(2)`

B

`(1)/(4)`

C

`(1)/(20)`

D

`(1)/(10)`

Text Solution

AI Generated Solution

The correct Answer is:
To find the coefficient of \( x^5 \) in the expansion of \( (1 - x) \log_e(1 - x) \), we can follow these steps: ### Step 1: Expand \( \log_e(1 - x) \) The Taylor series expansion for \( \log_e(1 - x) \) around \( x = 0 \) is given by: \[ \log_e(1 - x) = -x - \frac{x^2}{2} - \frac{x^3}{3} - \frac{x^4}{4} - \frac{x^5}{5} - \ldots \] ### Step 2: Multiply by \( (1 - x) \) Now, we need to multiply \( (1 - x) \) by the series we just obtained: \[ (1 - x) \log_e(1 - x) = (1 - x) \left( -x - \frac{x^2}{2} - \frac{x^3}{3} - \frac{x^4}{4} - \frac{x^5}{5} - \ldots \right) \] ### Step 3: Distribute \( (1 - x) \) Distributing \( (1 - x) \) gives us: \[ = -x - \frac{x^2}{2} - \frac{x^3}{3} - \frac{x^4}{4} - \frac{x^5}{5} + x^2 + \frac{x^3}{2} + \frac{x^4}{3} + \frac{x^5}{4} + \ldots \] ### Step 4: Combine like terms Now, we need to combine the terms that contribute to \( x^5 \): 1. From \( -\frac{x^5}{5} \) 2. From \( \frac{x^5}{4} \) Thus, the coefficient of \( x^5 \) is: \[ -\frac{1}{5} + \frac{1}{4} \] ### Step 5: Find a common denominator To combine these fractions, we find a common denominator, which is 20: \[ -\frac{1}{5} = -\frac{4}{20}, \quad \frac{1}{4} = \frac{5}{20} \] ### Step 6: Combine the fractions Now, adding these together: \[ -\frac{4}{20} + \frac{5}{20} = \frac{1}{20} \] ### Conclusion Thus, the coefficient of \( x^5 \) in the expansion of \( (1 - x) \log_e(1 - x) \) is: \[ \frac{1}{20} \] ### Final Answer The answer is \( \frac{1}{20} \). ---
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