Show that mean and variance of first n natural numbers is `(n+1)/(2)` and `(n^(2) - 1)/(12)`

The variance of first n natural number is:

The arithmetic mean of first n natural numbers, is

The arithmetic mean of first n odd natural numbers, is

The arithmetic mean of the squares of first n natural numbers is

The mean of first n odd natural number is (a) (n+1)/2 (b) n/2 (c) n (d) n^2

Statement - I : The variance of first n even natural numbers is (n^(2) - 1)/(4) Statement - II : The sum of first n natural numbers is (n(n+1))/(2) and the sum of the squares of first n natural numbers is (n(n+1)(2n+1))/(6)

The sum of first n odd natural numbers is 2n-1 (b) 2n+1 (c) n^2 (d) n^2-1

Calculate the mean and standard deviation of first n natural numbers.

Calculate the mean and standard deviation of first n natural numbers.

Find the mean and variance for each of the data : First n natural numbers