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The variance of 6,8,10,12,14,16,18,20,22...

The variance of 6,8,10,12,14,16,18,20,22,24 is

A

33

B

37

C

45

D

54

Text Solution

AI Generated Solution

The correct Answer is:
To calculate the variance of the data set \(6, 8, 10, 12, 14, 16, 18, 20, 22, 24\), we will follow these steps: ### Step 1: Calculate the Mean (\( \bar{x} \)) The mean is calculated using the formula: \[ \bar{x} = \frac{\sum x_i}{n} \] where \( \sum x_i \) is the sum of all data points and \( n \) is the number of data points. - Sum of the data points: \[ 6 + 8 + 10 + 12 + 14 + 16 + 18 + 20 + 22 + 24 = 150 \] - Number of data points (\( n \)): \[ n = 10 \] Now, calculate the mean: \[ \bar{x} = \frac{150}{10} = 15 \] ### Step 2: Calculate the Variance The variance is calculated using the formula: \[ \sigma^2 = \frac{\sum (x_i - \bar{x})^2}{n} \] Now, we will calculate \( (x_i - \bar{x})^2 \) for each data point: - For \( x_1 = 6 \): \[ (6 - 15)^2 = (-9)^2 = 81 \] - For \( x_2 = 8 \): \[ (8 - 15)^2 = (-7)^2 = 49 \] - For \( x_3 = 10 \): \[ (10 - 15)^2 = (-5)^2 = 25 \] - For \( x_4 = 12 \): \[ (12 - 15)^2 = (-3)^2 = 9 \] - For \( x_5 = 14 \): \[ (14 - 15)^2 = (-1)^2 = 1 \] - For \( x_6 = 16 \): \[ (16 - 15)^2 = (1)^2 = 1 \] - For \( x_7 = 18 \): \[ (18 - 15)^2 = (3)^2 = 9 \] - For \( x_8 = 20 \): \[ (20 - 15)^2 = (5)^2 = 25 \] - For \( x_9 = 22 \): \[ (22 - 15)^2 = (7)^2 = 49 \] - For \( x_{10} = 24 \): \[ (24 - 15)^2 = (9)^2 = 81 \] ### Step 3: Sum of Squared Deviations Now, sum all the squared deviations: \[ \sum (x_i - \bar{x})^2 = 81 + 49 + 25 + 9 + 1 + 1 + 9 + 25 + 49 + 81 = 330 \] ### Step 4: Calculate the Variance Now, substitute back into the variance formula: \[ \sigma^2 = \frac{330}{10} = 33 \] ### Final Answer The variance of the data set \(6, 8, 10, 12, 14, 16, 18, 20, 22, 24\) is \(33\). ---
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