The lines `2x-3y=5` and `3x-4y=7` are diameters of a circle of are 154 sq. units. Taking `pi=22/7`, show that the equation of the circle is `x^(2)+y^(2)-2x+2y=47`

If the lines 2x-3y=5 and 3x-4y=7 are the diameters of a circle of area 154 square units, then obtain the equation of the circle.

The lines 2x-3y=5 and 3x-4y=7 are the diameters of a circle of area 154 sq. units. Then the equation of the circle is x^2+y^2+2x-2y=62 x^2+y^2+2x-2y=47 x^2+y^2-2x+2y=47 x^2+y^2-2x+2y=62

If the lines 3x + y = 11 and x - y = 1 are the diameters of a circle of area 154 sq. units, then the equation of the circle is

If the lines 2x+3y+1=0 and 3x-y-4=0 lie along diameter of a circle of circumference 10pi , then show that the equation of the circle is x^(2)-y^(2)-2x+2y-23=0

If the lines 3x-4y-7 = 0 and 2x-3y-5=0 are two diameters of a circle of area 49pi square units, the equation of the circle is:

If the lines 2x+3y+1=0 and 3x-y-4=0 lie along diameters of a circle of circumference 10 pi , then the equation of the circle is

If the lines 2x + 3y + 1 = 0 and 3x - y-4 = 0 lie along two diameters of a circle of circumference 10 pi , then the equation of circle is (i) x^(2) + y^(2) + 2x + 2y + 23 = 0 (ii) x^(2) + y^(2) - 2x - 2y - 23 = 0 (iii) x^(2) + y^(2) - 2 x + 2y - 23 = 0 (iv) x^(2) + y^(2) + 2x - 2y + 23 = 0

If the lines x+y+3=0 and 2x-y-9=0 lie along diameters of a circle of circumference 8pi then the equation of the circle is :

Find the centre and radius of the circle 2x^(2)+2y^(2)=3x-5y+7

The line x+3y=0 is a diameter of the circle x^2+y^2-6x+2y=0