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Statement I: The circle with the points ...

Statement I: The circle with the points of intersectionof the line `3x+4y=12` with axes as extremities of a diameter is `x^(2)+y^(2)-4x-3y=0`
Statement II: The circle passing through (0,0) and making intercepts 8 and 6 on x,y axes, has its is (-4,2).
Which of above statement is false?

A

only I

B

only II

C

both I and II

D

neigther I nor II

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we will analyze both statements step by step. ### Statement I: **Claim:** The circle with the points of intersection of the line \(3x + 4y = 12\) with axes as extremities of a diameter is \(x^2 + y^2 - 4x - 3y = 0\). 1. **Find the intercepts of the line \(3x + 4y = 12\):** - To find the x-intercept, set \(y = 0\): \[ 3x + 4(0) = 12 \implies x = 4 \implies \text{Point: } (4, 0) \] - To find the y-intercept, set \(x = 0\): \[ 3(0) + 4y = 12 \implies y = 3 \implies \text{Point: } (0, 3) \] 2. **Identify the points as extremities of the diameter:** - The points of intersection are \(A(4, 0)\) and \(B(0, 3)\). 3. **Find the center of the circle:** - The center \(C\) of the circle is the midpoint of \(A\) and \(B\): \[ C\left(\frac{4 + 0}{2}, \frac{0 + 3}{2}\right) = C(2, 1.5) \] 4. **Calculate the radius:** - The radius \(r\) is half the distance between \(A\) and \(B\): \[ r = \frac{1}{2} \sqrt{(4 - 0)^2 + (0 - 3)^2} = \frac{1}{2} \sqrt{16 + 9} = \frac{1}{2} \sqrt{25} = \frac{5}{2} \] 5. **Write the equation of the circle:** - The equation of the circle in standard form is: \[ (x - 2)^2 + (y - 1.5)^2 = \left(\frac{5}{2}\right)^2 \] - Expanding this gives: \[ (x - 2)^2 + (y - 1.5)^2 = \frac{25}{4} \] - Converting to general form: \[ x^2 - 4x + 4 + y^2 - 3y + \frac{9}{4} - \frac{25}{4} = 0 \] - Simplifying: \[ x^2 + y^2 - 4x - 3y = 0 \] 6. **Conclusion for Statement I:** - Since the derived equation matches the given equation, **Statement I is true**. ### Statement II: **Claim:** The circle passing through \((0, 0)\) and making intercepts 8 and 6 on the x and y axes has its center at \((-4, 2)\). 1. **Identify the intercepts:** - The x-intercept is \(8\) (point \((8, 0)\)) and the y-intercept is \(6\) (point \((0, 6)\)). 2. **Find the center of the circle:** - The center of the circle is the midpoint of the intercepts: \[ C\left(\frac{8 + 0}{2}, \frac{0 + 6}{2}\right) = C(4, 3) \] 3. **Check the given center:** - The given center is \((-4, 2)\), which does not match the calculated center \((4, 3)\). 4. **Conclusion for Statement II:** - Since the calculated center does not match the given center, **Statement II is false**. ### Final Conclusion: - **Statement I is true.** - **Statement II is false.**
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