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The sides of a square are x =4, x = 7, y...

The sides of a square are `x =4, x = 7, y =1 ` and `y = 4 ` . The equation of the circumcircle of the square is `:`

A

`x^(2)+y^(2)-11x-5y+32=0`

B

`x^(2)+y^(2)-11x-5y+7=0`

C

`x^(2)+y^(2)-6x-5y+7=0`

D

`x^(2)+y^(2)-5x-2y+15=0`

Text Solution

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The correct Answer is:
A
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