The equation of the tangent to the circl...

The equation of the tangent to the circle `x^(2)+y^(2)-4x+4y-2=0` at (1,1) is

A

`2x+3y=13`

B

`3x+2y=13`

C

`2x+3y=sqrt(13)`

D

`3x+2y=sqrt(13)`

Verified by Experts

The correct Answer is:

A

Similar Questions

Explore conceptually related problems

The equation of the normal to the circle x^(2)+y^(2)+6x+4y-3=0 at (1,-2) to is

Find the equation of the tangent to the circle x^2 + y^2-30x+6y+109=0 at (4, -1)

The tangent to the circle x^(2)+y^(2)-4x+2y+k=0 at (1,1) is x-2y+1=0 then k=

Find the equation of the tangents to the circle x^(2)+y^(2)-4x+6y-12=0 which are parallel to x+y-8=0

Find the equation of the tangents to the circle x^(2)+y^(2)-4x-5y+3=0 which are inclined at 45^(@) with X axis.

Equation of the tangent to the circle x^(2)+y^(2)-2x+4y-4=0 which is parallel to the line 3x+4y-1=0 is

Find the equation of the tangent to x^(2) + y^(2) - 2x + 4y=0 " at" (3,-1) Also find the equation of tangent parallel to it.

Find the equation of the image of the circle x^(2)+y^(2)-6x-4y+12=0 by the line mirror x+y-1=0

Find the equations of the tangents to the circle x^(2) div y^(2)- 9, which are parallel to the line 3x div 4y = 0

Find the equation of tangents to circle x^(2)+y^(2)-2x+4y-4=0 drawn from point P(2,3).