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The circle x^(2)+y^(2)-2x+4y+4=0,x^(2)+y...

The circle `x^(2)+y^(2)-2x+4y+4=0,x^(2)+y^(2)+4x-2y+1=0` are

A

intersecting

B

touching externally

C

touching internally

D

one is lying inside the other

Text Solution

AI Generated Solution

The correct Answer is:
To determine the relationship between the two given circles, we will follow these steps: ### Step 1: Write the equations of the circles in standard form. The equations of the circles are given as: 1. \( S_1: x^2 + y^2 - 2x + 4y + 4 = 0 \) 2. \( S_2: x^2 + y^2 + 4x - 2y + 1 = 0 \) ### Step 2: Identify the center and radius of the first circle \( S_1 \). We can rewrite the equation \( S_1 \) in the standard form \( (x - h)^2 + (y - k)^2 = r^2 \). 1. Rearranging \( S_1 \): \[ x^2 - 2x + y^2 + 4y + 4 = 0 \] Completing the square for \( x \) and \( y \): \[ (x - 1)^2 - 1 + (y + 2)^2 - 4 + 4 = 0 \] This simplifies to: \[ (x - 1)^2 + (y + 2)^2 = 1 \] From this, we can see that the center \( C_1 \) is \( (1, -2) \) and the radius \( r_1 = 1 \). ### Step 3: Identify the center and radius of the second circle \( S_2 \). Now we will rewrite the equation \( S_2 \): 1. Rearranging \( S_2 \): \[ x^2 + 4x + y^2 - 2y + 1 = 0 \] Completing the square for \( x \) and \( y \): \[ (x + 2)^2 - 4 + (y - 1)^2 - 1 + 1 = 0 \] This simplifies to: \[ (x + 2)^2 + (y - 1)^2 = 4 \] From this, we can see that the center \( C_2 \) is \( (-2, 1) \) and the radius \( r_2 = 2 \). ### Step 4: Calculate the distance between the centers \( C_1 \) and \( C_2 \). Using the distance formula: \[ d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} \] Substituting the coordinates of \( C_1(1, -2) \) and \( C_2(-2, 1) \): \[ d = \sqrt{((-2) - 1)^2 + (1 - (-2))^2} = \sqrt{(-3)^2 + (3)^2} = \sqrt{9 + 9} = \sqrt{18} = 3\sqrt{2} \] ### Step 5: Compare the distance with the sum of the radii. Now we compare the distance \( d \) with the sum of the radii \( r_1 + r_2 \): \[ r_1 + r_2 = 1 + 2 = 3 \] Since \( d = 3\sqrt{2} \) and \( 3\sqrt{2} \) is greater than \( 3 \), this implies that the circles do not intersect and one circle lies inside the other. ### Conclusion: The circles are such that one is lying inside the other.
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